(w/w-5)-(4w/4w-5)=(w-2/4w^2-25w+25)

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Solution for (w/w-5)-(4w/4w-5)=(w-2/4w^2-25w+25) equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

w/w-(((4*w)/4)*w)-5+5 = w-((2/4)*w^2)-(25*w)+25 // - w-((2/4)*w^2)-(25*w)+25

(2/4)*w^2-(((4*w)/4)*w)-w+25*w+w/w-25-5+5 = 0

(2/4)*w^2-w^2-w+25*w+w/w-25-5+5 = 0

24*w-1/2*w^2-24 = 0

DELTA = 24^2-(-24*(-1/2)*4)

DELTA = 528

DELTA > 0

w = (528^(1/2)-24)/(-1/2*2) or w = (-528^(1/2)-24)/(-1/2*2)

w = 24-(4*33^(1/2)) or w = 24-(-4*33^(1/2))

w in { 24-(4*33^(1/2)), 24-(-4*33^(1/2)) }

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